Capacitor closing interval

Why does a capacitor look like a short for no time?

Until they charge, a cap acts like a short circuit, and an inductor acts like an open circuit. When you turn on an ideal switch from an ideal voltage source, to an ideal capacitor you get some odd solutions, in this case infinite current for an infinitesimal time. So it looks like a short for no time.

Why does a capacitor act like a short circuit at t 0?

Capacitor acts like short circuit at t=0, the reason that capacitor have leading current in it. The inductor acts like an open circuit initially so the voltage leads in the inductor as voltage appears instantly across open terminals of inductor at t=0 and hence leads.

What is the difference between a capacitor and a closed circuit?

Capacitor: at t=0 is like a closed circuit (short circuit) at 't=infinite' is like open circuit (no current through the capacitor) Long Answer: A capacitors charge is given by Vt = V(1 −e(−t/RC)) V t = V (1 − e (− t / R C)) where V is the applied voltage to the circuit, R is the series resistance and C is the parallel capacitance.

What happens if a capacitor is a short circuit?

(A short circuit) As time continues and the charge accumulates, the capacitors voltage rises and it's current consumption drops until the capacitor voltage and the applied voltage are equal and no current flows into the capacitor (open circuit). This effect may not be immediately recognizable with smaller capacitors.

Can the voltage across a capacitor change instantaneously?

What you have written is true; the voltage across a capacitor cannot change instantaneously. A similar thing holds for an inductor; the current through an inductor cannot change instantaneously. Yes, so would that mean that all the values at t=0- are the same as t=0+?

When does a capacitor act as an open circuit?

The capacitor acts as open circuit when it is in its steady state like when the switch is closed or opened for long time.